SOLUTION: Given that m<LKN = 145°
Angle LKM = (2x+10) Angle MKN = 4x-3
May you please explain how to do this as i am having a hard time!
Algebra.Com
Question 501872: Given that m
Angle LKM = (2x+10) Angle MKN = 4x-3
May you please explain how to do this as i am having a hard time!
Answer by cleomenius(959) (Show Source): You can put this solution on YOUR website!
It sounds as if angles LKM and MRN = LKN, which is 145 degrees.
2x + 10 + 4x - 3 = 145
6x + 7 = 145
6x = 138
x = 23
LKM = 2(23) + 10 = 56 degrees
MKN = 4(23) - 3 = 89 degrees
56 degrees + 89 degrees = 145 degrees.
This does check.
Cleomenius.
RELATED QUESTIONS
Yes I am having a problem solving geometry proofs the problem is as follows:... (answered by Alan3354)
Hi. I have a problem that I'm having difficulty solving, and I'm curious if I have even... (answered by Alan3354)
Hello
First of all in advance I thank you for the help you give me!
Okay so here is... (answered by solver91311,MathLover1)
Very confused here...
Suppose csc t = 4 and tan t > 0
sin(t - 6π) =... (answered by josmiceli,Edwin McCravy)
Given ST bisects angle RSV
m of angle RST =2x+3y
m of angle TSV = 3x-y+2
(answered by MathLover1)
10x+15=6x+3.....Could you explain how to do theses types of problems I am having a hard... (answered by stanbon,solver91311)
I am having a really hard time with this. Can you help me and explain in detail so I can... (answered by ReadingBoosters)
Given: ∠A is comp. to ∠B
∠C is comp. to ∠B
∠A = (3x+y)°... (answered by ikleyn,advanced_Learner,hussamuddin)
I am having a hard time with this question 3[2x] <= 12. how do i solve... (answered by tommyt3rd)