SOLUTION: <1=3x+12
<2=5x+4y
<3=x+6y
find <2
<2=<1
<3+<2=180
Algebra.Com
Question 501732: <1=3x+12
<2=5x+4y
<3=x+6y
find <2
<2=<1
<3+<2=180
Answer by cleomenius(959) (Show Source): You can put this solution on YOUR website!
It does not seem as if you stated the problem correctly, particularly angle 1.
Cleomenius.
RELATED QUESTIONS
1. points are (-4,7) and (2,x) m=-1/3, find for X
2. 1/2x-3/4y=-4
1/4x+3/2y=13... (answered by lynnlo)
x=6y-2... (answered by checkley75)
1/6(3x+5y)+2/3(3/5x-6y) (answered by ReadingBoosters)
Can you please help me divide rational expressions and find any restrictions.... (answered by pradhyumna.kumar@gmail.com)
(1) 3x+y=1
-6x-3y=-2
(2) 3x-5y=15
x-2y=8
(3)-2x+y=5
8x-4y=12... (answered by Alan3354)
-2+4y=1... (answered by roseo)
2x+3-3x+2+x-1=180
(answered by Jeff Gordon)
SOLVE THE SYSTEM BY ADDING OR SUBTITUTION
3X+6y=0
x=2/3
solve the sysem by adding... (answered by malakumar_kos@yahoo.com)
graph the following problems, #1 &2;
1.) 3x-5y = -9
5x-6y = -8
2.) 4x+5y = -2
(answered by lwsshak3)