SOLUTION: KM bisects <JKL, m<JKM= (4x+6)degrees, and m<MKL= (7x-12) degrees. Find m<JKM.
-> SOLUTION: KM bisects <JKL, m<JKM= (4x+6)degrees, and m<MKL= (7x-12) degrees. Find m<JKM.
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Geometry: Angles, complementary, supplementary angles
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The two angles are equal so we can solve for x.
4x + 6 = 7x - 12
18 = 3x
6 = x
4(6) + 6 = 30 degrees = angle JKM
7(6) - 12 = 30 degrees =angle MKL