SOLUTION: A. segment DG, segment EH, segment FT intersects O. 1.Name two linear pair of angles. 2.Name the two supplement of angle FOH. 3.Name the two supplement of angle GOI. 4.Angle GO

Question 485306: A. segment DG, segment EH, segment FT intersects O.
1.Name two linear pair of angles.
2.Name the two supplement of angle FOH.
3.Name the two supplement of angle GOI.
4.Angle GOH ang anle DOE are _____,_____,and _____.
B. Ray AL bisects angle KAT. Find the value of x.
1.measure of angle 3=6x, measure of angle KAT=90-x
2.measure of angle 1=7x+3, measure of angle 2=6x+7
3.measure of angle 1=5x-12, measure of angle 2=3x+6
4.measure of angle 1=x, maesure of angle 3=4x
5.measure of angle 1=2x-8, measure of angle 3=116
6.measure of angle 2=x+12, measure of angle 3=6x-20
C. solve the ff. problems:
1.Find the measure of an angle which is twice as large as its supplement.
2.An angle is half as a large as its complement,find its angle.
3.The measure of a supplement of an angle is 12 more than twice the measure of an angle. find the measures of an angle and its supplement.
4.A supplement of an angle is six times as large as its complement.Find the measures of the angle,its supplement and its complement.
5.In a certain linear pair, one angle measures twice as much as the other. what is the measure of the angle?
6.Three times the measure of the complement of a certain angle is equal to 30 more than the measure of a supplement of that angle.Find the measure of each angle.
Thanks..pls answer my questions right now if it is ok because i need it right now.its my assignment,thanks.
Answer by cleomenius(959) (Show Source): You can put this solution on YOUR website!
For part one, it looks like part one needs some form of a diagram,
I do not know what O is; is it a line?
Part two needs to have the angles 1,2,3 identified.
+++++++++++++++++++++++++++++++++++++++++++++++++++
So for part three.
1. 3x = 180
x = 60 degrees, the supplement is 120 degrees.
2. 3x = 90
x = 30, the complement is 60 degrees.
3. x + 12 = 2(180 - x)
x + 12 = 360 - 2x
3x = 348
x = 116 degrees, the supplement is 64 degrees.
To check, 64 * 2 = 128, - 12 degrees is 116.
4. 180 - x = 6(90 - x)
180 - x = 540 -6x
5x = 360
x = 72 degrees, the angle
complement = 18
supplement = 108
18 * 6 = 108 degrees.
5. A linear pair is 180 degrees.
3x = 180 degees,
x = 60 degrees.
2x = 120 degrees.
6. 3(90-x ) -30 = 180 - x
270 -3x - 30 = 180 - x
240 -3x = 180 - x
60 = 2x
30 degrees = x.
complement = 60
supplement = 150
3 * 60 = 180, 180 - 30 = 150 degrees for a check.
If you could clarify the first two parts we will look at them. They do not look too difficult with the proper information.
Cleomenius.

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