SOLUTION: if x+y +z+w=15, then at least k of the numbers x,y,z,w must be positive where k is

Algebra.Com
Question 444415: if x+y +z+w=15, then at least k of the numbers x,y,z,w must be positive where k is
Answer by richard1234(7193)   (Show Source): You can put this solution on YOUR website!
At least one of the numbers must be positive. For example, 18 + (-1) + (-1) + (-1) = 15.
RELATED QUESTIONS

Let w, x, y, and z be positive real numbers. If w + 2x + 3y + 6z = 8 - w^2 - x^2 - y^2 - (answered by CPhill,ikleyn)
all variables are positive integers what is the value of each ? X + Y + Z + W = 34 X ×... (answered by Boreal)
Let x and y be nonzero, real numbers such that -1 < x < 1 and -2 < y < 2. Suppose x/y +... (answered by richard1234)
If v,w, x,y, and z are positive consecutive integers whose sum is 0, then what is the... (answered by rfer)
The rate constant, k, of a certain reaction can be determined using the following... (answered by Boreal)
If w, x, y, and z are four nonzero numbers, then all of the following proportions are... (answered by AnlytcPhil)
For positive real numbers x, y, and z such that 3x = y(sqrt2)/3 = z(sqrt2)/3.1, which of... (answered by CubeyThePenguin)
w y - + - = x... (answered by jim_thompson5910)
If for three distinct positive numbers x, y, and z, {{{ y/(x-z) = (x+y)/z = x/y }}}... (answered by ikleyn)