SOLUTION: find the measure of an angle such the difference between the measure of its supplement and 3 times the measure of the complement is 16 degrees

Question 418577: find the measure of an angle such the difference between the measure of its supplement and 3 times the measure of the complement is 16 degrees
Found 2 solutions by Gogonati, stanbon:
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
Denote the unknown angle x degree, then its supplement is (180-x)degree and its complement is (90-x) degree. Since the difference between the supplement and three times the complement is 16 degree, we write the equation:
(180-x)-3(90-x)=16. The measure of unknown angle is 53 degree.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the measure of an angle such the difference between the measure of its supplement and 3 times the measure of the complement is 16 degrees
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angle: x
complement: 90-x
supplement: 180-x
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Equations:
180-x -(3(90-x)) = 16
180-x -270+3x = 16
2x - 90 = 16
2x = 106
x = 53 degrees
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Cheers,
Stan H.
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