SOLUTION: if i have a sin the equals .75 how does that equate to an angel of 37 degrees

Question 407805: if i have a sin the equals .75 how does that equate to an angel of 37 degrees
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

Just draw the unit circle and joggle a bit then all becomes clear.
sin^1(0.75) means "what angle gives " if you do the unit circle. You'll see that there is in the range degree that gives you that value.
Which is correct depends on what the problem is, what physical situation it is and so on.
=>
x = sin^-1(0.75) = 48.6 _degrees
and

x = sin^-1(0.75) = 131.41_degrees

If you calculate it equals
If you calculate it equals

RELATED QUESTIONS
Question: The measure of each interior angel of a regular polygon is eleven times that of (answered by stanbon)

If one-half of the complement of an angle plus three-fourths of the supplement of the... (answered by checkley71)

If I have a foundation .5 ft in width, 9ft deep and 260 ft in length - How many cubic... (answered by jim_thompson5910)

hi i have gotten the answer to the question, but don't know the reasoning behind it. our (answered by stanbon)

AH! I need help! In the convex quadrilateral ABCD if ,angel a is congruent to angel d (answered by mangopeeler07)

angel x has a supplementary angle measuring 37 degrees. what is the measure of angle... (answered by cleomenius)

How would I use a half-angle identity to find the exact value of sin 75... (answered by lwsshak3)

if one-half of the supplement of an angel is six degrees less than twice the complement... (answered by rfer)

if "n" arithmetic means�were�inserted between 75 and 19 such that the sum of the third... (answered by KMST)