SOLUTION: find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 10 degrees

Question 243385: find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 10 degrees
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 10 degrees
:
Let = the angle
then
(180-x) = it's supplement
and
(90-x) = it's complement
:
The equation for:
"the difference between the measures of its supplement and three times its complement is 10 degrees"
(180-x) - 3(90-x) = 10
:
180 - x - 270 + 3x = 10
:
Combine like terms:
-x + 3x + 180 - 270 = 10
:
2x - 90 = 10
:
2x = 10 + 90
:
2x = 100
x =
x = 50 degrees
:
:
Is this true?
(180-50) - 3(90-50) = 10
130 - 3(40) = 10; confirms our solution
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