SOLUTION: find two consecutive integers such that the larger, added to eight times thesmaller, equals 110

Question 229631: find two consecutive integers such that the larger, added to eight times thesmaller, equals 110
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Let x & x+1 be the 2 integers.
8x+x+1=110
9x=110-1
9x=109
x=109/9
x=12.111 is not an integer.
Did you mean to say 2 even integers?
If YES then:
8x+(x+2)=110
9x=110-2
9x-108
x=108/9
x=12 ans. for the sma;ller integer
12+2=14 ans. for the larger integer.
Proof:
8*12+14=110
96+14=110
110=110

RELATED QUESTIONS
PLEASE HELP....FIND TWO CONSECUTIVE EVEN INTEGERS SUCH THAT THE LARGER, ADDED TO EIGHT... (answered by jorel1380)

find two consecutive even integhers such that the larger, added to eight times the... (answered by orca)

Find two consecutive odd integers such that the larger, added to eight times the smaller, (answered by Maths68)

Write an equation, two consecutive odd integers such that the larger added to eight times (answered by tommyt3rd)

find two consecutive even integers such that the larger,added to eight times the smaller, (answered by checkley77)

Find two consecutive even integers such that twelve times the first equals eight times... (answered by malaydassharma)

Find two consecutive even integers such that twelve times the first equals eight times... (answered by Fombitz)

Find two consecutive even integers such that eight times the first equals seven times the (answered by oscargut)

Find two consecutive even integers such that the smaller added to two times the larger... (answered by Fombitz)