SOLUTION: find the masurement of each angle in the triangle.
(6n+31)
(5n-19)
(n+12)
now i tired 5n-19=180
-19+19=0
180+19=199
5n=199
5n*5=0
199*
Algebra.Com
Question 221104: find the masurement of each angle in the triangle.
(6n+31)
(5n-19)
(n+12)
now i tired 5n-19=180
-19+19=0
180+19=199
5n=199
5n*5=0
199*5=39.8
saying that my answer is 39.8
but i know this is wrong because it's multiple choice and it didnt fit so i didnt do the other ones yet
Found 2 solutions by Alan3354, jim_thompson5910:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find the masurement of each angle in the triangle.
(6n+31)
(5n-19)
(n+12)
-------------
I suppose those are the 3 angles ??
If so, they add up to 180º
12n + 24 = 180
12n = 156
n = 13
-------
Sub for n to find the 3 angles
109º
46º
25º
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Remember, all angles in a triangle add to 180 degrees. This means
Start with the given equation.
Remove the parenthesis.
Combine like terms on the left side.
Subtract from both sides.
Combine like terms on the right side.
Divide both sides by to isolate .
Reduce.
Now just plug this value into the given angles to get:
So the three angles are 109, 46, and 25 degrees.
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