SOLUTION: The first angle of a triangle is half the measure of the second angle. The measure of the third angle is 40 degress more than 4 times the measure of the first. Find the measure of
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Question 213818: The first angle of a triangle is half the measure of the second angle. The measure of the third angle is 40 degress more than 4 times the measure of the first. Find the measure of each angle.
Found 2 solutions by stanbon, RAY100:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The first angle of a triangle is half the measure of the second angle. The measure of the third angle is 40 degress more than 4 times the measure of the first. Find the measure of each angle.
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Let the 2nd angle be "x".
Then the 1st angle is "2x"
And the 3rd angle is "4x+40"
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Equation:
x + 2x + 4x+40 = 180
7x = 140
x = 20 degrees (2nd angle)
2x = 40 degrees (1st angle)
4x+40 = 120 degrees (3rd angle)
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Cheers,
Stan H.
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let x,,y,,,z,,,be angles of triangle
.
x = (1/2) y,,,,or y=2x,,,,,given
.
z= 40 + 4z,,,,,,,,given
.
but sum of angles = 180,,,or x + y + z = 180
.
x + 2x + 40 +4x = 180
.
7x = 140
.
x= 20
.
y=2x = 2*20 = 40
.
z=40 +4x =40 + 4*20 =40 + 80 = 120
.
.
checking,,,x+y+z=20+40+120 = 180,,,,,ok
.
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