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Let the measurement of the angle be A, then its supplement is 180-A, and, we are told that this is equal to 36 degrees less than twice the supplement of the complement of A (90-A). Did I get that right? So, in algebrese, this would look like:
180-A = 2(180-(90-A))-36 Simplify and solve for A, then we can find its supplement.
180-A = 2(180-90+A)-36
180-A = 2(90+A)-36
180-A = 180+2A-36
180-A = 144+2A Add A to both sides.
180 = 144+3A Subtract 144 from both sides.
36 = 3A Divide both sides by 3
A = 12 degrees. This is the measure of angle A, but we want its supplement, so...
180-A = 180-12 = 168 degrees.