SOLUTION: The supplement of an angle 36 degrees less than twice the supplementof the complement. find the measurement of thw supplement.

Question 155673This question is from textbook holt geometry
: The supplement of an angle 36 degrees less than twice the supplementof the complement. find the measurement of thw supplement. This question is from textbook holt geometry

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let the measurement of the angle be A, then its supplement is 180-A, and, we are told that this is equal to 36 degrees less than twice the supplement of the complement of A (90-A). Did I get that right? So, in algebrese, this would look like:
180-A = 2(180-(90-A))-36 Simplify and solve for A, then we can find its supplement.
180-A = 2(180-90+A)-36
180-A = 2(90+A)-36
180-A = 180+2A-36
180-A = 144+2A Add A to both sides.
180 = 144+3A Subtract 144 from both sides.
36 = 3A Divide both sides by 3
A = 12 degrees. This is the measure of angle A, but we want its supplement, so...
180-A = 180-12 = 168 degrees.
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