SOLUTION: to the nearest tenth of a degree, find the sizes of the acute angles in the right triangle whose hypotenuse is 2.5 times as long as its short leg.

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 Question 148271: to the nearest tenth of a degree, find the sizes of the acute angles in the right triangle whose hypotenuse is 2.5 times as long as its short leg.Found 2 solutions by vleith, Nate:Answer by vleith(2825)   (Show Source): You can put this solution on YOUR website!Assume the short side is adjacent to the hypotenuse. cos(z) = adjacent/hypotenuse = 1/2.5 To find z, use arccosine(1/2.5) = z = 23.6 So one angle is 23.6 degrees and the other one is 180-90-23.6 = 66.4degrees Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website! Let's begin with angle O. We need a trig identity that would include the opposite leg and the hypotenuse. _SOH_ CAH TOA sin O = x / 2.5x sin O = 1 / 2.5 sin O = 0.4 O = 23.6 degrees Angle Q = 90 - Angle O Angle Q = 90 - 23.6 Angle Q = 66.4 degrees