SOLUTION: A chord 18 inches long is perpendicular to the radius of a circle. The distance of the intersection of the chord and the radius to the center of the circle is 3 inches. What is the

Question 1188600: A chord 18 inches long is perpendicular to the radius of a circle. The distance of the intersection of the chord and the radius to the center of the circle is 3 inches. What is the radius of the circle? illustrate the circle and show your complete solution.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

The radius that is perpendicular to the chord bisects the chord. So the portion of that radius from the center to the chord, half of the chord, and a radius to the end of the chord form a right triangle; the lengths of the legs are 3 (given) and 9 (half of the chord length), and the hypotenuse is the radius of the circle.

Use the Pythagorean Theorem to answer the question.

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