SOLUTION: An oven rated at 750 W is switched on for 45 minutes per day. A refrigerator is rated at 2500 w and is on 8 hours per day. How much does it cost to operate BOTH the fridge and oven

Question 1179786: An oven rated at 750 W is switched on for 45 minutes per day. A refrigerator is rated at 2500 w and is on 8 hours per day. How much does it cost to operate BOTH the fridge and oven for 1 year if the price is $0.157 / kWh? (Include $ sign with no space and if necessary, round to two decimal places)/
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.


The used energy per day is

    
    750*0.75 + 2500*8 = 20562.5 watts-hours,  or   20.5625 kilowatts-hours.



(Here 0.75 stands for 45 minutes = 3/4 of an hour).



The used energy per year is  20.5625 kWh * 365  days.


The cost per year is  0.157 * 20.5625 * 365  dollars.


Use your calculator.

RELATED QUESTIONS
An operation is rated at 2,500 pieces per hour, and it takes you five hours to make 2,500 (answered by Alan3354)

You are trying to decide how to most efficiently use your oven. You do not want the oven... (answered by stanbon)

2. You are trying to decide how to most efficiently use your oven. You do not want the... (answered by Theo)

. A local factory currently assembles 160 ovens per day. The factory can sell each oven (answered by Theo)

You are trying to decide how to most efficiently use your oven. You do not want the oven... (answered by Fruglemiester1234)

2. You are trying to decide how to most efficiently use your oven. You do not want the... (answered by stanbon)

Translate the following situation into an inequality. Do not solve. �Marla plans to go (answered by stanbon)

On a travel website, 58 hotels are rated 5 stars, 120 hotels are rated 4 stars, 135... (answered by MathLover1,math_tutor2020,ikleyn)

his is another WORD PROBLEM that i do not understand how to do, can someone please help? (answered by vleith,stanbon)