SOLUTION: In the diagram below, \overline{FG} \cong \overline{HG}, FG ≅ HG , \overline{BD} \parallel \overline{EI} BD ∥ EI and \text{m}\angle ACB = 61^{\circ} .m∠

Question 1148276: In the diagram below, \overline{FG} \cong \overline{HG},
FG
≅
HG
, \overline{BD} \parallel \overline{EI}
BD
∥
EI
and \text{m}\angle ACB = 61^{\circ} .m∠ACB=61
∘
. Find \text{m}\angle FGH.m∠FGH.
Answer by greenestamps(13209) (Show Source): You can put this solution on YOUR website!

There is no diagram; and it is impossible to read the given information when presented in this fashion....

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