SOLUTION: m < a = 4x + 16 m < + 5x + 20 would it be: m < a = 4x + 16 m < + 5x + 20 = 90 9x + 36 = 90 ?

Algebra.Com
Question 1125314: m < a = 4x + 16 m < + 5x + 20
would it be:
m < a = 4x + 16 m < + 5x + 20 = 90
9x + 36 = 90 ?
Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.
What is written in this post, has nothing common with a way on how a Math problem should be presented.

So, the post 

    a)  MAKES NO SENSE,   and


    b)  in this form, does not deserve any consideration.


RELATED QUESTIONS

m/3+16=20 (answered by jim_thompson5910)
In triangle ABC, m(AB) = 8, m(BC) = 16, m∠x = 90° FIND m∠A (answered by Edwin McCravy)
In ∆ABC, m∠A = 3x + 1, m∠B = 4x - 17,and m∠C = 5x - 20. Which... (answered by Fombitz)
What is m? 5/16 =... (answered by oberobic)
I have a worksheet that states if angle 1 and angle2 are complementary angles and m... (answered by Earlsdon)
Algebra BD bicects (answered by cleomenius)
4x+5y=20... (answered by user_dude2008)
It is proposed to build a single circular park equal in area to the sum of areas of two... (answered by Theo)
< A and < B are complementary. Find m< A and m< B. m< A=5x+8 m< B=x+4 m< A=3x-7... (answered by jim_thompson5910)