SOLUTION: What is the equation of the line that is parallel to y=2x-7 and passes through (5, -1)

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Question 1108962: What is the equation of the line that is parallel to y=2x-7 and passes through (5, -1)
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39621)   (Show Source): You can put this solution on YOUR website!
For , will be parallel to your given line.







Equation of line slope 2, containing point (5,-1) is .
Answer by ikleyn(52818)   (Show Source): You can put this solution on YOUR website!
.
What is the equation of the line that is parallel to y = 2x-7 and passes through (5, -1)
~~~~~~~~~~~~~~~~~~~~~~~ 

The given line has the slope of 2.

Since the projected/requested line is parallel to the given line, it also has the slope of 2.

Hence, the projected/requested line has an equation of the form  y = 2x + b  with unknown coefficient "b".

To find "b", simply substitute the coordinates of the given point p and q as x and y respectively into this equation  y = 2x + b.  

You will get

    -1 = 2*5 + b,

which implies  b = -1 - 2*5 = -1 - 10 = -11.


Thus your final equation of the projected/requested straight line in slope-intercept form is 

y = 2x - 11.

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    - Equation for a straight line parallel to a given line and passing through a given point
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