SOLUTION: If m < EBC = 31a-2 and m < EBH = 4a+45, find m < HBC. Picture of the equation: https://i.imgur.com/ou44uBB.png I tried solving for 31a-2=4a+45 and got 47/27. My teacher gave

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Question 1094979: If m < EBC = 31a-2 and m < EBH = 4a+45, find m < HBC.
Picture of the equation: https://i.imgur.com/ou44uBB.png
I tried solving for 31a-2=4a+45 and got 47/27. My teacher gave a poor example and didn't really try explaining it to me. What am I supposed to do with the fraction part of the equation to solve for angle HBC?
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

If m < EBC = 31a-2 and m < EBH = 4a+45, find m < HBC.
Picture of the equation: https://i.imgur.com/ou44uBB.png
I tried solving for 31a-2=4a+45 and got 47/27. My teacher gave a poor example and didn't really try explaining it to me. What am I supposed to do with the fraction part of the equation to solve for angle HBC? 
You set ∡EBC = ∡EBH, but the 2 angles are not equal, so you CANNOT do that. And, as far as I see, none of the angles are equal.

Unless other info is given, ∡HBC will not have a NUMERICAL value.

∡EBC = 31a – 2		∡EBH = 4a + 45

∡EBH + ∡HBC = ∡EBC

4a + 45 + ∡HBC = 31a - 2 -------- Substituting 4a + 45 for ∡EBH, and 31a – 2 for ∡EBC

∡HBC  = 31a – 2 – 4a – 45

∡HBC =  

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