SOLUTION: MO bisects <LMN, m<LMO = 6x - 27 and m<NMO = 2x+33 solve for X and find m<LMN

Question 1092423: MO bisects
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Since MO is the bisector,

Then solve for LMN,

You can substitute without solving for x.

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