SOLUTION: MO bisects < LMN, m < LMO = 6x - 27 and m < NMO = 2x+33 solve for X and find m < LMN
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Question 1092388: MO bisects < LMN, m < LMO = 6x - 27 and m < NMO = 2x+33 solve for X and find m < LMN
Found 2 solutions by richwmiller, josgarithmetic:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Answer by josgarithmetic(39631) (Show Source): You can put this solution on YOUR website!
Angles LMO and NMO are congruent, of equal measures, so .
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