SOLUTION: Give the complement of :
48°50' (mins ) ' 35" ( sec.)
Algebra.Com
Question 1064290: Give the complement of :
48°50' (mins ) ' 35" ( sec.)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Give the complement of :
48°50' (mins ) ' 35" ( sec.)
-------------
Subtract it from 90 degs
---
89° 59' 60" = 90 degs
48° 50' 35"
----------------- Subtract
41° 9' 25"
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