in a quadrilateral STUV the bisectors of angle U and angle V meet at a point O. if angle T=80 and angle S=60. find angle UOV
OU is the bisector of ∠U, and OV is the bisector of ∠V
Note that OV and OU form 2 sides of the triangle, OVU
Let ∠SVO be x
Then ∠OVU also = x
Likewise, let ∠TUO be y
Then ∠OUV also = y
Since the interior angles of a quadrilateral sum to , we get:
2x + 2y + 60 + 80 = 360
2x + 2y + 140 = 360
2x + 2y = 220____2(x + y) = 2(110)_____x + y = 110
Since x and y are the 2 base angles of triangle, OVU, it follows that ∠UOV = 180 - (x + y), or 180 - 110 =