SOLUTION: Given: ∠A is comp. to ∠B ∠C is comp. to ∠B ∠A = (3x+y)° ∠B = (x+4y+2)° ∠C = (3y-3)° Find: m∠B (comp. = complementary) I w

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Question 1049483: Given: ∠A is comp. to ∠B
∠C is comp. to ∠B
∠A = (3x+y)°
∠B = (x+4y+2)°
∠C = (3y-3)°
Find: m∠B
(comp. = complementary)
I was thinking that since complementary angles are (90-x) you would figure out what x is by possibly adding angle A angle B and angle C all together and solving... I'm not sure if this is right. Would you use solving systems? I was thinking maybe you would because there's x and y you need to solve for. I am having a hard time understanding this concept.
Found 3 solutions by ikleyn, advanced_Learner, hussamuddin:
Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.
Your thinking is correct.

Go farther ahead!


Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
the are

= eq 1
= eq 2
= eq 1
= eq 2
= eq 1
= eq 2
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
We'll use substitution. After moving 5*y to the right, we get:
, or . Substitute that
into another equation:
and simplify: So, we know that y=12. Since , x=7.

Answer: .
Answer by hussamuddin(51)   (Show Source): You can put this solution on YOUR website!
you are right, go ahead
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