Tutors Answer Your Questions about Linear Algebra (FREE)
Question 29958: 3(2x-1)=27
Use the distributive Property!
3(2x)= 6x and 3(-1) = -3
so 6x-(-3)=27
6x+3=27 Now you must get the variable by itself on one side, so subtract 3 from both sides which will get you
6x+3-3=27-3 the +3-3 cancel eachother out, and 27-3 is 24.
6x=24 Now you must solve for the x variable, so you divide both sides by 6, which will give you 6x/6=24/6
The 6's cancel out, which leaves x on the left side, and 24 divided by 6 is 4, Hence, x=4.
Click here to see answer by ZachEdmo4590(2)  |
Question 30148: Question:
Solve the system: x^2+y^2=4
x+y=2
Possible solutions:
(a) [{2,-2), (-2,-2)]
(b) [{0,-2), (-2,0)]
(c) [(0,2), (2,0)]
(d) [(0,0), (2,-2)]
Please help thanks!
Click here to see answer by josmiceli(9686)  |
Question 30083: if f(a)=2a-1 and g(a)=a2, then g(f(a))=?
how does this work out step by step?
Thank you
f(a)=2a-1 If this is true, then that part of the problem (f(a))is solved! Te answer is 2a-1.
G(a)= a2 If this is true then the variable g and a or the same thing. I hope that that is "a" to the second notation!
the answer to this problem is g(2a-1)or
2ga-g or
2a2<---(second notation)-a
Click here to see answer by johnpaul(2) |
Question 30334: Question:
What can you say about the solutions of this nonlinear system?
y=4x^2+4
y=2x^2-4
(a) the system has no solution
(b) the system has two real solutions
(c) the system had two imaginary solutions
(d) the system has on solution of multiplicity 2.
Click here to see answer by josmiceli(9686) |
Question 30357: Use Descartes rule of signs to determine how many positive and how many negative real zeros that polynomial functions may have. Do not attmept to find the zeros.
f(x) =x^6-2x^5+4x^4+4x^3+5x^2=5x+3
(a) 5, 3, or 1 positive real zero; 2 or no negative real zeros
(b)4,2, or no positive real zeros; 2 or no negative real zeros
(c)2 or no positive real zeros; 4, 2, or no negatitive real zeros
(d) 4, 2, or no positive real zeros; 3 or 1 negative real zero
Click here to see answer by mukhopadhyay(490) |
Question 30362: Question: Find the equation of the ellipse whose center is (5,-3) that has a vertex at 13,-3) and a minor axis of lenght 10.
POssible Answers:
(A) (x-5)^2/64 + (y+3)^2/25 = 1
(B) (x+5)^2/64 + (y-3)^2/25 = 1
(C) x^2/64 + y^2/25 = 1
(D) none of these
Click here to see answer by venugopalramana(3286) |
Question 30331: Quesion: Which wquation below is the quadratic equation in standard form that results whsn you substitute u+x^-2 into the equation x^-4 -32 = 4x^-2 ?
Answers:
(a) 1/u^2 - 4/u -32 =0
(b) u^2 -4u -32 = 0
(c) u^4 -4u^2 -32 =0
(d) u^-2 -4u +32 = 0
(e) 1/u^2 +4/u -32 =o
Click here to see answer by Cintchr(481) |
Question 30332: Quesion: Which wquation below is the quadratic equation in standard form that results whsn you substitute u+x^-2 into the equation x^-4 -32 = 4x^-2 ?
Answers:
(a) 1/u^2 - 4/u -32 =0
(b) u^2 -4u -32 = 0
(c) u^4 -4u^2 -32 =0
(d) u^-2 -4u +32 = 0
(e) 1/u^2 +4/u -32 =o
Click here to see answer by Cintchr(481) |
Question 30460: Solve the system:
x^2+y^2=63
x^2-3y^2=27
(A) (3 sqrt 6, 3) (3 sqrt 6, -3) (-3 sqrt 6, 3) (-3 sqrt6, -3)
(B) (-3 sqrt6, 3) ( -3 sqrt6, -3)
(C) 3 sqrt6, 3) (3 sqrt 6, -3)
(D) 1, sqrt 62) (1, -swrt 62) (-1, sqrt 62) (-1, -sqrt 62)
Please be specific as to which letter answer is correct.
Thanks
Click here to see answer by mukhopadhyay(490) |
Question 30461: (8) Question:
Solve the system:
x^2 +y^2=20
x^2-2y^2=8
(THIS PROBLEM IS WRITTEN EXACTLY AS IT APPEARS!)
(A) (1, sqrt19) (1, -sqrt19) (-1, sqrt19), (-1, -sqrt19)
(B)(4,2) (4, -2)
(C) 04, 2) (-4, -2)
(D) 4, 2) (4, -2) (-4, 2) (-4, -2)
Please be specific as to which letter answer is correct
Thanks
Click here to see answer by mukhopadhyay(490) |
Question 30463: (M) Question:
Find the center, vertices, and foci for the ellipse:
4x^2+16y^2=64
(A) center (0,0) vertices (0, +4) foci (0, +3.5)
(B) center (2, 4) vertices (4, 0) and (4,8) foci (4, -1.5) and (4, 5.5)
(C) center (0,0) vertices (+4, 0) foci (+3.5,0)
(D) center (4,2) vertices (0,2) and (4,2) foci (0.5,2) and (7.5,2)
Please be specific as to whcih letter is correct
Click here to see answer by sdmmadam@yahoo.com(530) |
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