SOLUTION: Goes through intercepts (-2, 0) and (0, 4) help me how to graph that

Algebra ->  College  -> Linear Algebra -> SOLUTION: Goes through intercepts (-2, 0) and (0, 4) help me how to graph that      Log On


   



Question 996898: Goes through intercepts (-2, 0) and (0, 4) help me how to graph that
Found 2 solutions by rothauserc, MathLover1:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
intercepts are (-2, 0) and (0, 4)
use y = mx + b where m is the slope and b is the y intercept
m = (4 - 0) / (0 -(-2)) = 4/2 = 2, then
y = 2x + 4
here is the graph
+graph%28+400%2C+300%2C+-6%2C+5%2C+-10%2C+10%2C+2x%2B4%29+


Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

plot given points and draw a line through
then, find the equation of the line
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-2, 0) and (x2, y2) = (0, 4).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%284-0%29%2F%280--2%29+=+2.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 2%2A-2+%2Bb+=+4. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=0-2%2A-2+=+4.

y=(2)x + (4)

Your graph:





so your equation is y=2x+%2B+4