SOLUTION: How can I determine the zeros roots and interceptors of this third-degree polynomial function f ( x ) = x ^ 3 + x ^ 2-4x
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Question 984208: How can I determine the zeros roots and interceptors of this third-degree polynomial function f ( x ) = x ^ 3 + x ^ 2-4x
Found 2 solutions by Boreal, MathLover1:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x^3+x^2-4x=0 to find roots
factor out x
x(x^2+x-4)=0
x=0 is one root
x=(1/2)(-1+/- sqrt (1+16)) That works ;;;; sqrt 17=4.12
x=1.56, -2.56
y intercept =0,0
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
first make
...factor out
... this product will be equal to zero only if one or both of the factors is equal to zero
so, one root is
the other two roots we will get solving -use quadratic formula
exact solutions are:
and
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