SOLUTION: write the equation of the line that passes through (2 5) and perpendicular to the line 2y-3x=5. Write the answer in standard form.

Question 916968: write the equation of the line that passes through (2 5) and perpendicular to the line 2y-3x=5. Write the answer in standard form.
Found 2 solutions by JulietG, mananth:
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
There's an excellent explanation on finding the equation of a line written by tutor LongJohnSilver.
If you just need the answer, plug the values into tutor Jim Thompson's solver.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
-3 x + 2 y = 5
Find the slope of this line

2 y = 3 x + 5
Divide by 2
y = 1 1/ 2 x + 2 1/2
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = 1 1/2

The slope of a line perpendicular to the above line will be the negative reciprocal - 2/3
Because m1*m2 =-1
The slope of the required line will be - 2/3

m= - 2/3 ,point ( 2 , 5 )
Find b by plugging the values of m & the point in
y=mx+b
5 = -1 1/ 3 + b
b= 6 1/3
m= - 2/3
The required equation is y = - 2/ 3 x + 19/ 3

3y=-2x+19
2x+3y=19

m.ananth@hotmail.ca

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