SOLUTION: A man left A at 6:00 am expecting to reach B at 9:00 am. But after walking one hour, he was delayed for half an hour and so he had to increase his rate by 1 mile per hour to reach
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Question 903387: A man left A at 6:00 am expecting to reach B at 9:00 am. But after walking one hour, he was delayed for half an hour and so he had to increase his rate by 1 mile per hour to reach B at 9:00 am. Find his speed before the delay and the distance between A and B.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
______________rate_________time_________distance
_______________r___________3____________r*3=d
before interr___r___________1_____________r*1
after interr____r+1_________1_____________(r+1)*1
-
-
Sum of before and after interruption d distance.
Expected regular travel ;
, equating the distance
-----walking speed, before interruption.
-----travel distance.
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