SOLUTION: [(3/4^2-5)-(2/5-4*2)]/(2*3^3/2+2^2)

SOLUTION: [(3/4^2-5)-(2/5-42)]/(23^3/2+2^2)

Question 892569: [(3/4^2-5)-(2/5-4*2)]/(2*3^3/2+2^2)
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!

Apply order of operations, applying exponents first

Now do one round of multiplication and division. The 3/16 operation is deferred

Now perform the division 18/2

Next simplify (3/16-5). = =
Now simplify = = =
Putting it together

A common denominator for the top is 5*16 = 80

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Notice that a good solver such as wolframalpha will give you
the above result. Try entering ((3/4^2-5)-(2/5-4*2))/(2*3^3/2+2^2) at
www.wolframalpha.com
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