SOLUTION: Determining an orthogonal basis for W = {(x, y, z); x - 2y + z = 0}.
Algebra.Com
Question 892544: Determining an orthogonal basis for W = {(x, y, z); x - 2y + z = 0}.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Choose any vector in W.
Set , then
If , then
(0,1,2)
.
.
.
Now use the dot product to find a perpendicular vector to this vector.
Let
then
Let , then
(1,-2,1)
.
.
.
Now take the cross product of those two vectors to find a mutually perpendicular vector to these two.
(0,1,2)X(1,-2,1)=(5,2,-1)
So then,
(0,1,2), (1,-2,1), and (5,2,-1) form an orthogonal basis of W.
RELATED QUESTIONS
X+y+z+w=6
2x+3y-w=0
-3x+4y+z+2w=4... (answered by Alan3354)
Please solve for w, x, y, and z.
1. x + 3w = 4
2y - z -w = 0
3y - 2w = 1
(answered by CharlesG2)
w+x-y+z=0
w-2x-2y-z=-5
w-3x-y+z=4
2w-x-y+3z=7
find the four variables and please show (answered by Alan3354)
Solve
w+x-y+z=0
w-2x-2y-z=5
w-3x-y+z=4... (answered by Edwin McCravy)
w y
- + - =
x... (answered by jim_thompson5910)
Use the elimination method to solve the system of equation that has four variables.... (answered by Alan3354)
2w+x-3y+z=4
w-3x+y+z=32
-w+2x+2y-z=-10... (answered by Fombitz,Alan3354)
x+2y+z=5
0+y+-z=3
0+0+2z=6
solve for x,y,and... (answered by checkley71)
x+2y+0z+3w=0
0x+y+z+w=1
0x+y+0z+w=2... (answered by Alan3354)