SOLUTION: determine the radius of a circle, to the nearest tenth,given its centre and a point on the circumference centre(4,-1),Point(7,-7)

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Question 887720: determine the radius of a circle, to the nearest tenth,given its centre and a point on the circumference centre(4,-1),Point(7,-7)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Find the distance between the two points

Solved by pluggable solver: Distance Formula


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (4, -1), we can say (x1, y1) = (4, -1)
So x%5B1%5D+=+4, y%5B1%5D+=+-1


Since the second point is (7, -7), we can also say (x2, y2) = (7, -7)
So x%5B2%5D+=+7, y%5B2%5D+=+-7


Put this all together to get: x%5B1%5D+=+4, y%5B1%5D+=+-1, x%5B2%5D+=+7, and y%5B2%5D+=+-7

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Now use the distance formula to find the distance between the two points (4, -1) and (7, -7)



d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29


d+=+sqrt%28%284+-+%287%29%29%5E2+%2B+%28-1+-+%28-7%29%29%5E2%29 Plug in x%5B1%5D+=+4, y%5B1%5D+=+-1, x%5B2%5D+=+7, and y%5B2%5D+=+-7


d+=+sqrt%28%284+-+7%29%5E2+%2B+%28-1+%2B+7%29%5E2%29


d+=+sqrt%28%28-3%29%5E2+%2B+%286%29%5E2%29


d+=+sqrt%289+%2B+36%29


d+=+sqrt%2845%29


d+=+sqrt%289%2A5%29


d+=+sqrt%289%29%2Asqrt%285%29


d+=+3%2Asqrt%285%29


d+=+6.70820393249937

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Answer:


The distance between the two points (4, -1) and (7, -7) is exactly 3%2Asqrt%285%29 units


The approximate distance between the two points is about 6.70820393249937 units



So again,


Exact Distance: 3%2Asqrt%285%29 units


Approximate Distance: 6.70820393249937 units





The exact radius is r+=+3%2Asqrt%285%29

The radius is approximately

Round to the nearest tenth to get 6.7 and this is your final answer.