SOLUTION: The circumferences of a front and rear wheels of a carriage are, respectively, 2 and 4 feet. What distance will the carriage have passed over when the front wheel has made 8 more r

Question 887244: The circumferences of a front and rear wheels of a carriage are, respectively, 2 and 4 feet. What distance will the carriage have passed over when the front wheel has made 8 more revolutions than the rear wheel?
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
= distance the carriage will have passed over when the front wheel has made 8 more revolutions than the rear wheel.
= revolutions made by the front wheel.
= revolutions made by the rear wheel.
The problem says that when the carriage passed over the distance
the front wheel will have made 8 ore revolutions than the rear wheel, so

Multiplying both sides of the equal sign times gets rid of denominators, to get
--->--->
Subtracting from both sides of the equal sign gives us
--->
The carriage will have passed over a distance of feet.

That would take revolutions for the front wheel and revolutions for the rear wheel.
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