SOLUTION: Find the vertex, focus and directrix and the correct graph of the equation 12(x+5)=y-8)^2

Question 881377: Find the vertex, focus and directrix and the correct graph of the equation 12(x+5)=y-8)^2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the vertex, focus and directrix and the correct graph of the equation 12(x+5)=y-8)^2
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12(x+5)=y-8)^2
(y-8)^2=12(x+5)
This is an equation of a parabola that opens rightward
Its basic equation: (y-k)^2=4p(x-h), (h,k)=coordinates of the vertex
For given equation:
vertex: (-5,8)
axis of symmetry: y=8
4p=12
p=4
focus: (-1,8) (p-distance to the right of vertex on the axis of symmetry)
directrix: x=-9 (p-distance to the left of vertex on the axis of symmetry)
see graph below:
y=�(12x+60)^.5+8

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