SOLUTION: 1. x^2+y^2=16 y=-x^2-4
2. x^2-y^2=61 x^2-y^2=11
The directions are solve the system of liner or non-linear equations but im not sure how
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Question 823171: 1. x^2+y^2=16 y=-x^2-4
2. x^2-y^2=61 x^2-y^2=11
The directions are solve the system of liner or non-linear equations but im not sure how
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1. x^2+y^2=16 y=-x^2-4
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x^2 = y-4
Substitute for "x^2" and solve for "y":
y-4 + y^2 = 16
-----
y^2 + y - 20 = 0
Factor:
(y+5)(y-4) = 0
y = -5 or y = 4
-----
Solve for "x":
x^2 = y-4
If y = -5, x^2 = -9
Therefore y = -5 is extraneous.
---
If y = 4, x^2 = 4-4 = 0
Then x = 0
---
Solution:: (0,4)
===================
2.
x^2-y^2=61
x^2-y^2=11
----
Subtract to get:
0 = 50
That is a contradiction.
---
There are no solutions.
============================
Cheers,
Stan H.
===============
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