Hi,

log(x+3)=1-logx     |Note:  x > 0

log(x+3) + logx = 1

log x(x+3)= 1

   x(x+3) = 10^1

   x^2 + 3x - 10 = 0

  (x+5)(x-2) = 0  x = 2 (tossing out negative solution as x must be >0

CHECKING our answer***

 log 2*5 = 1

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