SOLUTION: I dont know how to solve this: 3/A - 4/B = 8/C
Solving for B
Lcd should be abc if im not mistaken.
I get so far as 3bc - 4ac = 8ab. But then haven't a clue what to do...
Am i d
Algebra.Com
Question 806270: I dont know how to solve this: 3/A - 4/B = 8/C
Solving for B
Lcd should be abc if im not mistaken.
I get so far as 3bc - 4ac = 8ab. But then haven't a clue what to do...
Am i doing it wrong?
Found 2 solutions by richwmiller, solver91311:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
bring the b 's to one side
3bc - 4ac = 8ab
3bc-8ab=4ac
b(3c-8a)=4ac
b=(4ac)/(3c-8a)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Step 1: Swear on the life of your first born that you will never again treat an upper case letter and a lower case letter as the same variable. A is not A, b is not B, and c is not C.
Step 2: Isolate the term with the
in it:
Apply the LCD of
to the LHS only:
Take the reciprocal of both sides and multiply by 4
John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
I dont know how to solve this: 3/A - 4/B = 8/C
Lcd should be abc if im not mistaken.
(answered by richwmiller)
Hi am slightly stuck on this question on number theory. I have solved it up to a point... (answered by Alan3354)
Solve: {{{ (5-b)/b + 3/4 = 7/b }}}
So far, I applied the LCD method to this. My LCD... (answered by josgarithmetic,ikleyn,MathTherapy)
I am trying to solve y=x2-6x. so far column x is 0 1 2 3 4 column y is 0 -5 -8 a=1... (answered by KnightOwlTutor)
a=b+3(4-c) b=5 c=2 what is a ,i need to know how the process is done to get the value... (answered by jim_thompson5910)
I couldn't work letter C and #2, please assist.
Please check the rest of the work and... (answered by yuendatlo,solver91311)
I have 3 questions:
1) I= nE/(nr+R) (solve for n)
2) 1/a + 1/b = c (solve for... (answered by edjones)
hello,
I am having trouble finiding the lcd for this equation. Id appreciate the help... (answered by Alan3354,MathLover1,stanbon)