You can
put this solution on YOUR website! 4 and 3 + i among its roots
Another complex root must be the conjugate of 3+i, ie 3-i.
The corresponding quadratic monic equation is x^2 -6 x + 10 = 0 (why?)
[Hint: in one step sum and product of 3+i & 3-i]
Hence, f(x) = (x-4)(x^2 -6 x + 10)
Kenny