SOLUTION: Fred has $5.50 in change in his pocket, all in dimes and quarters. he
has 37 coins in all. How many dimes does he have?
Algebra.Com
Question 761831: Fred has $5.50 in change in his pocket, all in dimes and quarters. he
has 37 coins in all. How many dimes does he have?
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
x = dimes
y = quarters
x + y = 37...1
10x + 25y = 550..2
Multiply (1) by 10
10x + 10y = 370...3
10x + 25y = 550...2
subtract (3) from (2)
15y = 180
y = 12
Substitute y = 12 into (1)
x + y = 37
x + 12 = 37
x = 37 - 12
x = 25
So, there are 25 dimes + 12 quarters.
Hope this helps.
:-)
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