SOLUTION: How many negative real zeros are possible for a polynomial function f(x), given that f(−x) has 9 variations in sign?

SOLUTION: How many negative real zeros are possible for a polynomial function f(x), given that f(−x) has 9 variations in sign?

Algebra.Com

Question 758417: How many negative real zeros are possible for a polynomial function f(x), given that f(−x) has 9 variations in sign?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
There are 9 sign changes for f(-x), so there are at most 9 negative real zeros possible.
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