SOLUTION: The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should i

Algebra.Com
Question 7540: The period of a simple pendulum is directly proportional to the
square root of its length. If a pendulum has a length of 6 feet and a
period of 2 seconds, to what length should it be shortened to achieve
a 1 second period?

Found 2 solutions by Earlsdon, Merhuza:
Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Write the proportion:
Substitute the given values of p (2 secs) and l (6 ft.) and solve for k.

Now you can write:
Square both sides to find l.
Now substitute the values for and then solve for l.



l = 1.5 ft.

Answer by Merhuza(5)   (Show Source): You can put this solution on YOUR website!
l=6/4
=1.5ft

RELATED QUESTIONS

The length of a simple pendulum varies directly with the square of its period. If a... (answered by Fombitz)
The period of a simple pendulum is directly proportional to the square root of its... (answered by funmath,josmiceli)
The period of a simple pendulum is directly proportional to the square root of its... (answered by Nate)
the period of a simple pendulum is directly proportional to the square root of its... (answered by Earlsdon)
Please help me with this problem: The period of a simple pendulum is directly... (answered by stanbon,AnlytcPhil)
The period of a simple pendulum is directly proportional to the square root of its... (answered by stanbon)
The period of a simple pendulum is directly proportional to the square root of its... (answered by jim_thompson5910)
The period of a simple pendulum is directly proportional to the square root of its... (answered by stanbon)
THE PEROD OF A SIMPLE PENDULUM IS DIRECTLY PROPORTIONAL TO THE SQUARE ROOT OF ITS LENGTH. (answered by uma)