SOLUTION: 6[x-(2-x)]=-4(8x+3)
Algebra.Com
Question 742650: 6[x-(2-x)]=-4(8x+3)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
6[x-(2-x)]=-4(8x+3)
-----
6(2x-2) = -32x-12
----
12x-12 = -32x-12
20x = 0
x = 0
===============
Cheers,
Stan H.
===============
RELATED QUESTIONS
subtract
(5x^2 + 9x^4 - 2x^3 - 3) - (8x^6 - 8x^5 + x^4 -... (answered by jim_thompson5910)
8x-3(6+x)=5x+4 (answered by jim_thompson5910)
8x-3(x-1)=4(x+2) (answered by checkley75)
8x+2=7(x-4)+6 (answered by RAY100)
(8x+12)^½ =... (answered by stanbon)
Minimum value of x^8-8x^6+19x^4-12x^3+14x^2-8x+9... (answered by Fombitz)
x^2+8x=6 (answered by jim_thompson5910)
Please Factor:
{{{ 8x^2 * ( x-6)^3 - 4x(x-6)^4... (answered by Fombitz)