SOLUTION:
how many ounces of a 30% alcohol solution must be mixed with 40 ounces of an 80% alcohol solution to obtain a 70% alcohol solution?
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Question 720329:
how many ounces of a 30% alcohol solution must be mixed with 40 ounces of an 80% alcohol solution to obtain a 70% alcohol solution?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
.40*80+.30X=.40(70+X)
32+.30X=28+.40X
.30X-.40X=28-32
-.10X=-4
X=-4/-.10
X=40 OUNCES OF 30% SOLUTION IS USED.
PROOF:
.40*80+.30*40=.40(70+40)
32+12=.40*110
44=44
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