SOLUTION: Since a logarithm is an exponent, how do you think the log property logb(xy) = logb (x) + logb (y) is related to the exponent property (b^m)(b^n) = b^(m+n)?

Question 6831: Since a logarithm is an exponent, how do you think the log property
logb(xy) = logb (x) + logb (y) is related to the exponent property
(b^m)(b^n) = b^(m+n)?
Answer by prince_abubu(198) (Show Source): You can put this solution on YOUR website!
First let

So then . The equivalent exponent for that log equation is .

Now, let's put back the logs in place of the J (un-substitute):

.

Remember the rule that says

Applying that above exponential rule, .

Remember the rule . In this case, and . So we're all cool.

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