SOLUTION: Solve Linear Systems Algebraically. x+ 4y = 1 3x + 2y = -12 and 3x + 2y = 6 x-4y = -6 Pleas help, Clari

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Question 680747: Solve Linear Systems Algebraically.
x+ 4y = 1
3x + 2y = -12
and
3x + 2y = 6
x-4y = -6
Pleas help, Clari

Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
1 x + 4 y = 1 .............1

3 x + 2 y = -12 .............2
Eliminate y
multiply (1)by 1
Multiply (2) by -2
1 x 4 y = 1
-6 x -4 y = 24
Add the two equations
-5 x = 25
/ -5
x = -5
plug value of x in (1)
1 x + 4 y = 1
-5 + 4 y = 1
4 y = 1 + 5
4 y = 6
y = 2
x= -5
y= 2
---------------
3 x + 2 y = 6 .............1

1 x -4 y = -6 .............2
Eliminate y
multiply (1)by 2
Multiply (2) by 1
6 x 4 y = 12
1 x -4 y = -6
Add the two equations
7 x = 6
/ 7
x = 1
plug value of x in (1)
3 x + 2 y = 6
3 + 2 y = 6
2 y = 6 -3
2 y = 3
y = 2
x= 1
y= 2

m.ananth@hotmail.ca

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