SOLUTION: Find vertex form of 25-x^2 and graph. I am completely lost and my notes aren't helping!

Question 668793: Find vertex form of 25-x^2 and graph.
I am completely lost and my notes aren't helping!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
y = 25-x^2

y = -x^2 + 25

y = -1*x^2 + 25

y = -1*(x-0)^2 + 25

The equatin is now in the form y = a(x-h)^2 + k

This is known as vertex form, where (h,k) is the vertex

We can see that h = 0 and k = 25

So the vertex is (0, 25)

Here's the graph (using a graphing calculator)

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