SOLUTION: for the equation {{{3x^3+ax^2-9x+6=0}}}, the sum of the roots is twice the product of the roots. Find a.

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Question 66153: for the equation 3x%5E3%2Bax%5E2-9x%2B6=0, the sum of the roots is twice the product of the roots. Find a.
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
3x^3+ax^2-9x+6=0
x^3+(a/3)x^2-3x+2=0
Sum of roots = -a/3
Product of roots = 2
Eqution:
Sum = 2*Product
-a/3=2*2
a=-12
Cheers,
Stan H.