SOLUTION: Trying to help my son logically solve following problem (rather than using guess and check):
(t^2) + m = 28
t + (m^2) = 148
Solve for t and m.
Thanks
Algebra.Com
Question 66103: Trying to help my son logically solve following problem (rather than using guess and check):
(t^2) + m = 28
t + (m^2) = 148
Solve for t and m.
Thanks
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
t^2 + m = 28
t + m^2 = 148
Set same terms to one side such as "t":
t^2 = 28 - m
t = 148 - m^2
Square the bottom:
t^2 = 28 - m
t^2 = 21,904 - 296m^2 + m^4
Negate the top (could the bottom i guess):
-t^2 = -28 + m
t^2 = 21,904 - 296m^2 + m^4
Add:
0 = m^4 - 296m^2 + m + 21,876
Relative Coordinates
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