SOLUTION: The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field
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Question 65979: The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field
Answer by uma(370) (Show Source): You can put this solution on YOUR website!
Let the width of the field be x ft.
So length = (2x-5) ft
Perimeter = 2[ length + width]
==> 2[2x-5+x] = 230
==> 2{3x-5} = 230
==> 6x - 10 = 230
==> 6x - 10 + 10 = 230 + 10
==> 6x = 240
==> 6x/6 = 240/6
==> x = 40
Thus the width of the field = 40 ft.
Length = 2x-5
= 2*40 - 5
= 80 - 5
= 75
Width = 40 ft and length = 75 ft
Good Luck!!!
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